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15n^2+31n=0
a = 15; b = 31; c = 0;
Δ = b2-4ac
Δ = 312-4·15·0
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{961}=31$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(31)-31}{2*15}=\frac{-62}{30} =-2+1/15 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(31)+31}{2*15}=\frac{0}{30} =0 $
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